F(-x)=4x^2+4x-4

Solution for F(-x)=4x^2+4x-4 equation:

(-F)=4F^2+4F-4

We move all terms to the left:

(-F)-(4F^2+4F-4)=0

We add all the numbers together, and all the variables

(-1F)-(4F^2+4F-4)=0

We get rid of parentheses

-4F^2-1F-4F+4=0

We add all the numbers together, and all the variables

-4F^2-5F+4=0

a = -4; b = -5; c = +4;
Δ = b2-4ac
Δ = -52-4·(-4)·4
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{89}}{2*-4}=\frac{5-\sqrt{89}}{-8}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{89}}{2*-4}=\frac{5+\sqrt{89}}{-8}
$